# What are the odds of getting the different cards?

內容目錄

## 1. The probability of a leopard

Each number can have 4 leopard combinations, a total of 13 numbers, can have 52 combinations, the probability is about 0.23%, and it will only appear once in every 400 cards.

## 2. Chances of a straight flush in fried golden flowers

Each suit can have 12 straight flush combinations, a total of 4 suits, 48 combinations, the probability is 0.21%, slightly lower than the leopard.

## 3. The probability of fried golden flowers and golden flowers

There are 274 combinations of the same suit in each suit, a total of 4 suits, and 1096 combinations! The probability is 4.95%, with an average of 20 cards appearing once.

## 4. The probability of a straight

Compared with a straight flush, after the first card is selected, the original card that must be selected each time becomes 4 cards, so the combination of a straight should be 16 times that of a straight flush.

Of course, the straight flush itself must be excluded, so the number of combinations of the straight is 48*15=720, and the probability is 3.2%.

An average of 30 occurrences. As a straight that is smaller than the golden flower, the probability of occurrence is relatively low.

## 5. The probability of frying golden flower pairs

4*3/2*12*4*13=3744 types, the probability of occurrence is about 16.94%

## 6. The probability of fried Jinhua scattered cards

22100-52-48-1096-720-3744=16440 species, the probability of occurrence is about 74.39%.

From the statistics above, it can be seen that the probability of a straight flush is lower than that of leopards; In addition, you can also know that it is very good to have more than a pair, and the total probability of occurrence is 25.61%; it is even more difficult to have a total of 8.67% if there are more than one straight. It is quite powerful if you can get a pair of cards when playing Jinhua, and you don’t have to have a straight Jinhua to compare cards.

## The probability of frying golden flowers

In addition to the 3 kings, there are 49 remaining cards for playing Jinhua. The probability of the first card being A is 1/49, the probability of the second being A is 3/48, and the probability of the third card being A is 1/49. The probability of being A is 2/47. If the player gets 3 k in his hand, the probability of winning in the end is high.

Probability problems have a core formula in the process of solving problems: the number of methods that occur is divided by the total number of methods. Next, let’s take a look at the relevant knowledge points of classical probability. Classical probability has two characteristics:

Features: Finiteness, that is, all basic events are limited.

Example 1. What is the probability of a dice throwing 3?

The number of ways a dice rolls 3 is 1, and the total number of ways is 6 (1, 2, 3, 4, 5, 6).

So the probability of a 3 on a die is 1 in 6.

Example 2. What is the probability that a dice rolls an even number?

The number of ways a dice rolls an even number is 3 (2, 4, 6), and the total number of ways is 6 (1, 2, 3, 4, 5, 6), so the probability of a dice rolling an even number is half.

Way of thinking: Among the numbers from 1 to 10, what is the probability that a number is larger than 5 and smaller than 8?

Feature 2: Equal possibility, that is, the probability of occurrence of each basic event is equal.

Example 3. Choose 3 out of 8 students with an equal number of boys and girls as the host of the school’s New Year’s Day party. What is the probability that boy and girl B will be selected at the same time?

Each student has the same probability of being selected as the host. Now A and B are selected at the same time. The number of times this happens is 6, that is, one of the remaining 6 students can be selected. And the total number of ways for this event to happen is to choose 3 students from 8 students, so the probability of this event happening is 3/28.

Then knowing the specific characteristics of the question type, how to use it in the actual problem-solving process? The following will take you to look at a few sample questions so that you can master this method proficiently.

Example 1. There are ten small balls numbered 1-10 in a bag, and two small balls are randomly selected from it. What is the probability that the sum of the numbers on these two small balls is exactly 6?

The desired event is that the number of the two small balls is exactly 6, and the number of ways to occur is 2, that is, 1+5, 2+4. The probability sought is 2 in 45.

Through the description of the question stem,lodi 777 casino login first figure out what the desired event is, and then calculate the number of methods and the total number of methods of the desired event, and use the formula to calculate the desired probability.

Example 2. Choose any two cards from the five cards with 1, 2, 3, 4, and 5 on them. The first card is used as the tens digit, and the second card is used as the ones digit. What is the probability of this even number?

The desired event is an even number of this number, that is to say, the ones digit of this number can be an even number, and there is no requirement for the tens digit.

The probability of the desired event is 2/5.

When calculating the probability, it is necessary to first judge the key information of the desired event based on the information of the conditions, and then use the methods learned to find the number of methods and the total number of methods of the event, and finally use the formula to find the probability of the target event.

Finding probability is not only applicable to fried gold, but also can be used in daily life to deduce the probability you want to know. You can practice it while playing the game.